On Saturday, Aug. 12, the South Asian community in Austin will come together to celebrate the inclusion of their heritage at the historic Texas State Capitol’s south steps. The Parade of India is a festival of cultural diversity in observance of India’s 71st Independence Day. It is open to all and no tickets are needed to attend this family-friendly event.
India gained independence from the British Empire on Aug. 15, 1947 following an Independence Movement noted for largely nonviolent resistance and civil disobedience led by the Indian National Congress. The holiday is observed throughout India with flag-hoisting ceremonies, parades and cultural events.
The program will start at 10 a.m. with a presentation of the U.S. and Indian national anthems, followed by speeches by State Rep. Celia Israel, of Texas’ House District 50, and Mayor Steve Adler. The parade will showcase groups representing the unique costumes, music and dances from each state in India, as well as local South Asian organizations. Bollywood Dances will be presented by students of Monsoon Dance in the State Capitol rotunda. There will be several information booths along with free Indian food samples and henna artists.
The Parade of India is hosted by Monsoon Dance in partnership with the Indian American Coalition of Texas, Hindu Swayamsevak Sangh, and Children Rights and You Austin Chapter.
This is the fourth annual celebration of Indian-American heritage at the State Capitol and each year marks a greater attendance of hundreds of Austinites coming together to honor cultural diversity in the U.S. Last year, Austin Mayor Steve Adler and State Rep. Celia Israel graced the parade by dancing with the cultural groups and joining as one with the members of the community in attendance.
Everyone is invited to join this festive and the Parade of India, as a colorful celebration of freedom, pride and culture.